Marbles In A Jar Probability

So the probability of getting a blue marble is 13 42.

Marbles in a jar probability.

Two marbles are drawn without replacement. A draw the tree diagram for the experiment. Answer in decimal rounded off to 2 decimal places. Total number of marbles 23 4 27 marbles p green marble of green marbles of marbles total 4 27 0 148 so the probability is 4 27 which is about a 14 8 chance.

The total number of marbles in the second jar is 42 marbles and the total number of blue marbles in the jar is 13. At least 1 red a jar contains 30 red marbles 12 yellow marbles 8 green marbles and 5 blue marbles. The chance is 2 in 5 but after taking one out the chances change. P getting a color other than red p 25 55 455 probability of this happening 3 times in a row is found by 455 455 455 094 example 2.

B find probabilities for p bb p br p rb p ww p at least one red p exactly one red. What is the maximum probability. Pose questions to the children about each of the jars and the probability of picking certain colored marbles. Have the children take turns answering the questions and placing the probability cards in front of each jar after each of the questions.

Remember there is one less marble in the jar. Place the possible card in front of the jar. What is the probability that you pick 3 green no red 1 of each at least 1 blue marble if a jar contains 5 blue 3 green and 4 red marbles. Find the probability of picking green 4 20 then find the probability of picking blue 5 19.

So the next time. A jar contains 4 black marbles and 3 red marbles. 13 is a prime number and 42. For example if the answer is 2 3 the response should be 0 67.

If we got a red marble before then the chance of a blue marble next is 2 in 4. Finally multiply the probabilities and reduce to get 1 19.